SolutionHard
Question
Two liquids X and Y form an ideal solution. At 300K, vapour pressure of the solution containing 1 mol of X and 3 mol of Y is 550 mm Hg. At the same temperature, if 1 mol of Y is further added to this solution, vapour pressure of the solution increases by 10 mm Hg. Vapour pressure (in mmHg) of X and Y in their pure states will be, respectively :
Options
A.200 and 300
B.300 and 400
C.400 and 600
D.500 and 600
Solution
PT = Pxoxx + Pyoxy
xx = mol fraction of X
xy = mol fraction of Y
∴ 550 = Pxo
+ Pyo 
∴ 550 (4) = Pxo + 3Pyo ........(1)
Further 1 mol of Y is added and total pressure increases by 10 mm Hg.
∴ 550 + 10 = Pxo
+ Pyo
∴ 560 (5) = Pxo + 4Pyo ........(2)
By solving (1) and (2)
We get, Pxo = 400 mm Hg
Pyo = 600 mm Hg
xx = mol fraction of X
xy = mol fraction of Y
∴ 550 = Pxo
+ Pyo ∴ 550 (4) = Pxo + 3Pyo ........(1)
Further 1 mol of Y is added and total pressure increases by 10 mm Hg.
∴ 550 + 10 = Pxo
+ Pyo∴ 560 (5) = Pxo + 4Pyo ........(2)
By solving (1) and (2)
We get, Pxo = 400 mm Hg
Pyo = 600 mm Hg
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