Question

Calculate E°_cell corresponding to each compound under going disproportionation reaction. The reaction for which E°_cell comes out +ve is spontaneous.
HBrO $\to$Br₂                 E° = 1.595, SRP (cathode)
HBrO $\to$Br$O_3^{-}$           E° = –1.5V, SOP (Anode)
2HBrO$\to$ Br₂ + Br$O_3^{-}$ 
E°_cell = SRP (cathode) – SRP (Anode)
= 1.595 – 1.5
= 0.095 V
E°_cell > 0 $\Rightarrow ∆$G° < 0 [spontaneous]