JEE Advanced | 2018Atomic StructureHard
Question
One mole of a monatomic ideal gas undergoes a cyclic process as shown in the figure (whre V is the volume and T is the temperature). Which of the statements below is (are) true ?

Options
A.
Process I is an isochoric process
B.
In process II, gas absorbs heat
C.
In process IV, gas releases heat
D.
Processes I and II are not isobaric
Solution

(A) Process-I is not isochoric, V is decreasing.
(B) Process-II is isothermal expansion
U = 0, W > 0
Q > 0
(C) Process-IV is isothermal compression,
U = 0, W < 0
Q < 0
(D) Process-I and III are NOT isobaric because in isobaric process T V hence isobaric T–V graph
will be linear.
Create a free account to view solution
View Solution FreeMore Atomic Structure Questions
When an ideal diatomic gas is heated at constant pressure, the fraction of the heat energy supplied which increases the ...The smallest wavelength of Lyman series is 91 nm . The difference between the largest wavelengths of Paschen and Balmer ...Cv and Cp denote the molar specific heat capacities of a gas at constant volume and constant pressure, respectively. The...The wavelengths involved in the spectrum of deuterium (12D) are slightly different from that of hydrogen spectrum, becau...the ratio of kinetic energy to the total energy of an electron in a Bohr orbit of the hydrogen atom, is :-...