JEE Main | 2014Chemical Kinetics and Nuclear ChemistryHard

Question

For the non-stoichiometre reaction 2A + B → C + D, the following kinetic data were obtained in three separate experiments, all at 298 K.
     
The rate law for the formation of C is

Options

A. = k[A][B]
B. = k[A]2[B]
C. = k[A][B]2
D. = k[A]

Solution

2A + B → C + D
Rate of Reaction
       
Let rate of Reaction = k[A]x[B]y
Or, = k[A]x[B]y
Now from table,
1.2 × 10-3 = k [0.1]x[0.1]y         .......(i)
1.2 × 10-3 = k [0.1]x[0.2]y         .......(ii)
2.4 × 10-3 = k [0.2]x[0.1]y         .......(iii)
Dividing equation (i) by (ii)
⇒    
⇒    
⇒    
Now Dividing equation (i) by (iii)
⇒    
⇒    
⇒    
Hence = K[A]1[B]0.

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