JEE Main | 2014ElectrochemistryHard
Question
Resistance of 0.2 M solution of an electrolyte is 50 Ω. The specific conductance of the solution is 1.4 S m-1. The resistance of 0.5 M solution of the same electrolyte is 280 Ω. The molar conductivity of 0.5 M solution of the electrolyte in S m2 mol-1 is
Options
A.5 × 10-4
B.5 × 10-3
C.5 × 103
D.5 × 102
Solution
For 0.2 M solution
R = 50 Ω
σ = 1.4 Sm-1 = 1.4 × 10-2 S cm-1]
⇒
Ω cm
Now, R = ρ
⇒
= 50 × 1.4 × 10-2
For 0.5 M solution
R = 280 Ω
σ = ?
= 50 × 1.4 × 10-2
⇒ R = ρ
⇒
⇒ ρ
× 50 × 1.4 × 10-2
× 70 × 10-2
= 2.5 × 10-3 S cm-1
Now, λm
= 5 S cm2 mol-1
= 5 × 10-4 S m2 mol-1
R = 50 Ω
σ = 1.4 Sm-1 = 1.4 × 10-2 S cm-1]
⇒
Ω cm Now, R = ρ
⇒
= 50 × 1.4 × 10-2 For 0.5 M solution
R = 280 Ω
σ = ?
= 50 × 1.4 × 10-2 ⇒ R = ρ
⇒
⇒ ρ
× 50 × 1.4 × 10-2 × 70 × 10-2= 2.5 × 10-3 S cm-1
Now, λm
= 5 S cm2 mol-1
= 5 × 10-4 S m2 mol-1
Create a free account to view solution
View Solution FreeMore Electrochemistry Questions
Pt | Cl2 (P1 atm) | HCl (0.1 M) | Cl2 (P2 atm) | Pt, cell reaction will be spontaneous if...A depolarizer used in dry cell batteries is...Assertion :- BeSO4 is more soluble in water than BaSO4.Reason :- In BeSO4 H.E. exceeds its L.E....Anthracene, C14H10, can be oxidized to anthraquinone, C14H8O2. What weight of anthraquinone can be produced by the passa...The standard reduction potential of Cu2+ / Cu and Cu2+ / Cu+ are 0.339V and 0.153 V respectively. The standard electrode...