ElectrochemistryHard

Question

Element A (atomic mass = 112) and element B (atomic mass = 27) form chlorides. Solutions of these chlorides are electrolysed separately and it is found that when the same quantity of electricity is passed, 5.6 g of A was deposited while only 0.9 g of B was deposited. The valency of B is 3. The valency of A is

Options

A.1
B.2
C.3
D.4

Solution

$n_{eq}A = n_{eq}B$

Or, $\frac{5.6}{112} \times V_{A} = \frac{0.9}{27} \times 3$

$\therefore$Valency of A , VA = 2.

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