JEE Main | 2014Current Electricity and Electrical InstrumentHard
Question
In a large building, there are 15 bulbs of 40 W, 5 bulbs of 100 W, 5 fans of 80 W and 1 heater of 1 kW. The voltage of the electric mains is 220 V. The minimum capacity of the main fuse of the building will be :
Options
A.8 A
B.10 A
C.12 A
D.14 A
Solution
15 × 40 + 5 × 100 + 5 × 80 + 1000 = V × I
600 + 500 + 400 + 1000 = 220 I
I =
= 11.36
I = 12 A.
600 + 500 + 400 + 1000 = 220 I
I =
= 11.36I = 12 A.
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