Current Electricity and Electrical InstrumentHard
Question
Consider a circuit with a constant current source of IC = 2mA with a capacitor of 2μF and resistor of 5kΩ (as shown in figure). At t = 0 the switch is closed. IC & IR denotes current in the capacitor & resistor branch respectively and VC represents potential difference across the capacitor. Choose the correct graph(s).


Options
A.

B.

C.

D.

Solution
At t = 0, capacitor act a short circuit & current in resistor branch = 0.
At t = ∞, iR = 2 mA ; iC = 0
At t = ∞, iR = 2 mA ; iC = 0
Create a free account to view solution
View Solution FreeTopic: Current Electricity and Electrical Instrument·Practice all Current Electricity and Electrical Instrument questions
More Current Electricity and Electrical Instrument Questions
In the following circuit the current flowing the 1kΩ resistor is :-...The total length of potentiometer wire AB is 50 cm in the arrangement as shown in figure. If P is the point where the ga...In the circuit shown below. The reading of the voltmeter V is : -...Express which of the following setups can be used to verify Ohm′s law : -...A micro-ammeter has a resistance of 100 Ω and full scale range of 50 mA. It can be used as a voltmeter and an ammet...