Hard
Question
A body has an initial velocity of 3 ms-1 and has a constant acceleration of 1 ms-2 normal to the direction of the initial velocity. Then its velocity, 4 second after the start is
Options
A.7 ms-1 along the direction of initial velocity
B.7 ms-1 along the normal to the direction of the initial velocity
C.7 ms-1 mid-way between the two directions
D.5 ms–1 at an angle of tan-1 4/5 with the direction of the initial velocity
Solution
u = 3m/s î a = 1ĵ m/s2
a is ⊥ u
so V after 4 sec
V = u + at
V = 3î + 1ĵ × 4
V = 3î + 4ĵ
= 5 m/s
and tan θ =
θ = tan-1
with the direction of the initial velocity.
a is ⊥ u
so V after 4 sec
V = u + at
V = 3î + 1ĵ × 4
V = 3î + 4ĵ
= 5 m/sand tan θ =
θ = tan-1
with the direction of the initial velocity.Create a free account to view solution
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