Hard
Question
The velocity at the maximum height of a projectile is half of its initial velocity u. Its range on the horizontal plane is:
Options
A.
B.
C.
D.
Solution
At maximum height v = u cos θ
= v ⇒ 
u cos θ ⇒ cos θ = 
⇒ θ 60o
R =
=
= v ⇒ u cos θ ⇒ cos θ = ⇒ θ 60oR =
=
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