KinematicsHard

Question

A projectile is projected angle (α > 45o) with an initial velocity u. The time t, which its magnitude of horizontal velocity will equal the magnitude of vorticity is : -

Options

A.t = u/g (cos α - sin α)
B.t = u/g (cos α + sin α)
C.t = u/g (sin α - cos α)
D.t = u/g (sin2 α - cos2 α)

Solution


= u cos αî + (u sin α - gt)
∵
u cos α = usin α - gt ⇒ t = (sin α - cos α)

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