KinematicsMedium
Question
A projectile is projected angle (α > 45o) with an initial velocity u. The time t, which its magnitude of horizontal velocity will equal the magnitude of vorticity is : -
Options
A.t = u/g (cos α - sin α)
B.t = u/g (cos α + sin α)
C.t = u/g (sin α - cos α)
D.t = u/g (sin2 α - cos2 α)
Solution
= u cos αî + (u sin α - gt)∵
u cos α = usin α - gt ⇒ t =
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