Hard
Question
A particle moves along the parabolic path y = ax2 in such a way that the x component of the velocity remains constant, say c. The acceleration of the particle is
Options
A.ac 
B.2ac2 ĵ
C.ac2 ĵ
D.a2c ĵ
Solution
ax = 0, Vy = dy/dt = 2ax dx/dt = 2axvx obtain ay = dvy/dt
y = ax2 ..........(1)
given Vx = C
from (1)
= 2a x.
Vy = 2ax .C ..........(2)
from (2)
= 2ac. 
ay = 2acVx
ay = 2ac2
= 2ac2 ĵ
y = ax2 ..........(1)
given Vx = C
from (1)
= 2a x.Vy = 2ax .C ..........(2)
from (2)
= 2ac. ay = 2acVx
ay = 2ac2
= 2ac2 ĵCreate a free account to view solution
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