KinematicsHard
Question
A particle is projected from a tower as shown in figure, then the distance from the foot of the tower where it will strike the ground will be : - (take g = m/s2)
Options
A.4000 / 3 m
B.5000 / 3 m
C.2000 m
D.3000 m
Solution
- 1500 = 
sin 37o × t - 
× 10 × t2 ; t = ?
Distance =
cos 37o × t(Horizontal)
⇒ x =
m
sin 37o × t - × 10 × t2 ; t = ? Distance =
cos 37o × t(Horizontal)⇒ x =
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