KinematicsHard
Question
In the figure the ends P and Q of an unstretchable string move downwards with uniform speed v. Mass M moves upward with speed
Options
A.v cos θ
B.
C.2v cos θ
D.
Solution
here x2 = y2 + d2
So 2x
= 2y 
⇒ 
= 
(v) = 
Component of velocity along string must be same so
vM cos θ (90 - θ) = v ⇒ vM =
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