KinematicsHard
Question
In the figure the ends P and Q of an unstretchable string move downwards with uniform speed v. Mass M moves upward with speed
Options
A.v cos θ
B.
C.2v cos θ
D.
Solution
here x2 = y2 + d2
So 2x
= 2y 
⇒ 
= 
(v) = 
Component of velocity along string must be same so
vM cos θ (90 - θ) = v ⇒ vM =
Create a free account to view solution
View Solution FreeMore Kinematics Questions
Two particle A & B projected along different directions from the same point P on the ground with the same velocity of 70...L, C and R represent he physical quantities inductance, capacitance and resistance respectively. The combinations which ...A gun is set up in such a way that the muzzle is at ground level as in figure. The hoop A is located at a horizontal dis...A ball is thrown eastward across level ground. A wind blows horizontally to the east, and assume that the effect of wind...If T is the total time of flight, H the maximum height and R is the horizontal range of a projectile, then x and y co - ...