Laws of MotionMedium
Question
Two blocks ′A′ and ′B′ each of mass ′M′ are placed on a smooth horizontal surface. Two horizontal forces F and 2F are applied on the two blocks ′A′ and ′B′ respectively as shown in figure. The block A does not slide on block B. Then the normal reaction acting between the two blocks is :
Options
A.F
B.F/2
C.F/√3
D.3F
Solution
(D)
Acceleration of two mass system is a =
leftward
FBD of block A
N cos 60o − F = ma =
solving N = 3 F
Acceleration of two mass system is a =
leftward FBD of block A
N cos 60o − F = ma =
solving N = 3 F Create a free account to view solution
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