Laws of MotionHard
Question
In the arrangement show in figure, coefficient of friction between the two block is μ = 
. The force of friction acting between the two block is
. The force of friction acting between the two block isOptions
A.8N
B.10N
C.6 N
D.4 N
Solution
Acceleration of system = 
= 3 ms-2
For upper block w.r.t. lower block
f = F1 + ma = 2 + 2 (3) = 8N
= 3 ms-2For upper block w.r.t. lower block
f = F1 + ma = 2 + 2 (3) = 8N
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