Laws of MotionHard
Question
In the arrangement show in figure, coefficient of friction between the two block is μ = 
. The force of friction acting between the two block is
. The force of friction acting between the two block isOptions
A.8N
B.10N
C.6 N
D.4 N
Solution
Acceleration of system = 
= 3 ms-2
For upper block w.r.t. lower block
f = F1 + ma = 2 + 2 (3) = 8N
= 3 ms-2For upper block w.r.t. lower block
f = F1 + ma = 2 + 2 (3) = 8N
Create a free account to view solution
View Solution FreeMore Laws of Motion Questions
A block of mass m resting on a wedge of angle θ as shown in the figure. The wedge is given an acceleration a toward...In the pulley system show in figure the movable pulleys, A, B , and C are of mass 1 kg each. D and E are fixed pulleys. ...Three equal weights of mass 2 kg each are hanging on a string passing over a fixed pulley as shown in fig. What is the t...A force applied on a mass is represented as and accelerates with 1 m/s2. What will be the mass of the body :-...The rocket engine lift a rocket from the earth, beacause hot gases :...