Laws of MotionMedium
Question
A block is kept on a smooth inclined plane of angle of inclination 300 that moves with a constant acceleration so that block does not slide relative to the plane . Let F1 be the contact force between the block and the plane . Now the inclined planed stop and let F2 be the contact force between the two in this case . Then F1/F2
Options
A.1
B.
C.2
D.
Solution
FBD of block :
∴ mgsin 30o = macos 30o
a = g tan 30o =
N = mg cos 30o + ma cos 60o
= mg ×
+ m × 
× 
F1 =
N = F2 =
∴
∴ mgsin 30o = macos 30o
a = g tan 30o =
N = mg cos 30o + ma cos 60o
= mg ×
+ m × × F1 =
N = F2 =
∴
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