Photoelectric EffectHard
Question
for maximum λ = 
(n1 = 2 → n2 = 1 Lymen
(n1 = 3 → n2 = 2 Balmer
Longest λLymen =
Longest λBalmer =
The electron in a hydrogen atom makes a transition from an excited state to the ground state. Which of the following statements is true ?
(n1 = 2 → n2 = 1 Lymen
(n1 = 3 → n2 = 2 Balmer
Longest λLymen =
Longest λBalmer =
The electron in a hydrogen atom makes a transition from an excited state to the ground state. Which of the following statements is true ? Options
A.Its kinetic energy increases and its potential and total energies decreases
B.Its kinetic energy decreases, potential energy increases and its total energy remains the same
C.Its kinetic and total energies decrease and its potential energy increases
D.Its kinetic, potential and total energies decrease
Solution
Kinetic energy (K.E.) = 
Potential (P.E.) =
Total energy (T.E.) =
When an electron in H-atom makes a transition from an excited state to the ground state, value of n decrease, hence K.E. increases and its P.E. & T.E. decreases.
Potential (P.E.) =
Total energy (T.E.) =
When an electron in H-atom makes a transition from an excited state to the ground state, value of n decrease, hence K.E. increases and its P.E. & T.E. decreases.
Create a free account to view solution
View Solution FreeMore Photoelectric Effect Questions
An electron is accelerated from rest, between two points A and B at which the potentials are 20V and 40 V respectively. ...The given graph shows the variation of √f vs z for characteristics X-rays. Lines 1, 2, 3, 4 shown in the graph cor...The unit of luminous efficiency of an electric bulb is:...The illuminance of a surface distant 10m from a light source is 10 lux. The luminous intensity of the source for normal ...The energy of the reaction Li1 + p 2 He4 is (the binding energy per nucleon in Li7 and He4 nuclei are 5.60 and 7.06 MeV ...