Photoelectric EffectHard
Question
The orbital speed of the electron in the ground state of hydrogen is v. What will be its orbital speed when it is excited to the energy state − 3.4 eV ?
Options
A.2 v
B.v/2
C.v/4
D.v/8
Solution
E ∝
n2 = 2
v ∝
(z = 1) ⇒ v2 = 
....... (B)
n2 = 2v ∝
(z = 1) ⇒ v2 = ....... (B)Create a free account to view solution
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