KTGHard
Question
A thermally insulated chamber of volume 2V0 is divided by a frictionless piston of area S & mass m into two equal parts A and B.Part A has an ideal gas at pressure P0 and temperature T0 and in part B is vacuum. A massless spring of force constant K is connected with the piston and the wall of the container as shown. Initially the spring is undeformed. The gas in chamber A is allowed to expand. Let in equilibrium the spring is compressed by x0 . Then :


Options
A.Pressure of the gas at equilibrium is 
B.Work done by the gas is 
C.Increase in internal energy of the gas is 
D.Increase in internal energy of the gas is
Solution
Temperature of the gas is decreased
(A) (D)

For equilibrium of piston
PS = Kx0
P =
For piston
Wall = KE2 − KE1
Wgas −
kx2 =
mv2
Wgas =
kx2 +
mv2 = position
ᐃQ = 0
ᐃQ = ᐃU + W
ᐃU = − W = negative
As internal energy of gas decreases ∴ temperature of gas decreases.
(A) (D)

For equilibrium of piston
PS = Kx0
P =
For piston
Wall = KE2 − KE1
Wgas −
Wgas =
ᐃQ = 0
ᐃQ = ᐃU + W
ᐃU = − W = negative
As internal energy of gas decreases ∴ temperature of gas decreases.
Create a free account to view solution
View Solution FreeMore KTG Questions
Ratio of molecular specific heats of a di- atomic gas will be :-...Oxygen and hydrogen gases are at temperature T. Then the K.E of molecules of oxygen gas is equal to how many times of K....A ring shaped tube contains two ideal gases with equal masses and atomic mass numbers M1 = 32 and M2 = 28. The gases are...In a process the pressure of a gas is inversely proportional to the square of the volume. If temperature of the gas incr...If a container is filled with the mixture of H2 and O2 then :-...