ThermodynamicsMedium
Question
In the above question, if the work done on the system along the curved path ′ba′ is 52J, heat abosrbed is
Options
A.− 140 J
B.− 172 J
C.140 J
D.172 J
Solution
ᐃU = Qacb − Wacb = 200 − 80 = 120 J
ᐃU = Qba − Wba , − 120 = Qba + 52 , Qba = − 172 J.
ᐃU = Qba − Wba , − 120 = Qba + 52 , Qba = − 172 J.
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