FrictionHard
Question
In the arrangement shown in the figure mass of the block B and A are 2 m,, 8 m respectively. Surface between B and floor is smooth. The block B is connected to block C by means of a pulley. If the whole system is released then the minimum value of mass of the block C so that the block A remains stationary with respect to B is : (Co-efficient of friction between A and B is m and pulley is ideal)
Options
A.
B.
C.
D.
Solution
(D) FBD of A
A FBD
If the acceleration of ′C′ is a
For block ‘A’ N = 8 ma .... (1)
8 mg − μN = 0 .... (2)
and acceleration a can be written by the equation of system (A + B + C)
m1 g = (10 m + m1) a .... (3)
8 mg =
10 m + m1 = μ m1
10 m = (μ − 1) m1 ⇒ m1 =
Ans.
A FBD
If the acceleration of ′C′ is a
For block ‘A’ N = 8 ma .... (1)
8 mg − μN = 0 .... (2)
and acceleration a can be written by the equation of system (A + B + C)
m1 g = (10 m + m1) a .... (3)
8 mg =
10 m + m1 = μ m1
10 m = (μ − 1) m1 ⇒ m1 =
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