FrictionHard
Question
A block of mass m placed on a rough inclined plane of inclinationθ = 30o can be just prevented from sliding down by applying a force F1 up the plane and it can be made to just slide up the plane by applying force F2 up the plane. If the coefficient of friction between the block and the inclined plane is 1/2√3 , the relation between F1 and F2 is :-
Options
A.F2 = F1
B.F2 = 2F1
C.F2 = 3F1
D.F2 = 4F1
Solution
F1 = mg sin 30 - f
= mg sin 30 - umg cos 30
F1 =
F2 = mg sin 30 + f
= mg sin 30 + μmg cos 30
= mg sin 30 - umg cos 30
F1 =
F2 = mg sin 30 + f
= mg sin 30 + μmg cos 30
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