FrictionHard
Question
A block lying on a long horizontal conveyor belt moving at a constant velocity receives a velocity 5 m/s relative to the ground in the direction opposite to the direction of motion of the conveyor. After t = 4 sec, the velocity of the block becomes equal to the velocity of the belt. The coefficient of friction between the block and the belt is 0.2. Then the velocity of the conveyor belt is : (g = 10 m/s2)
Options
A.13 m/s
B.−13 m/s
C.3 m/s
D.6 m/s
Solution
Since there is relative motion between block and conveyor, there will be frictional force = μN = 0.2 × m × 10
retardation =
= 2 m/sec2
Now v = u + at
⇒ v = 5 + (−2) 4
= −3 = 3 m/s opposite so the direction of initial velocity of the block.
retardation =
= 2 m/sec2 Now v = u + at
⇒ v = 5 + (−2) 4
= −3 = 3 m/s opposite so the direction of initial velocity of the block.
Create a free account to view solution
View Solution FreeMore Friction Questions
Given in the figure are two blocks A and B of weight 20 N and 100 N, respectively. These are being pressed against a wal...A horizontal force of 10 N is necessary to just hold a block stationary against a wall. The coefficient of friction betw...A solid cube of mass 5 kg is placed on a rough horizontal surface, in xy-plane as shown. The friction coefficient betwee...A block of mass m = 10 kg rests on a horizontal table. The coefficient of friction between the block and thetable is 0.0...Two projectiles are projected with the same velocity. If one is projected at an angle of 30o and the other at 60o to the...