Fluid MechanicsHard
Question
There is a small hole in the bottom of a fixed container containing a liquid upto height ′h′. The top of the liquid as well as the hole at the bottom are exposed to atmosphere. As the liquid comes out of the hole. (Area of the hole is ′a′ and that of the top surface is ′A′) :
Options
A.the top surface of the liquid accelerates with acceleration = g
B.the top surface of the liquid accelerates with acceleration = 
C.the top surface of the liquid retards with retardation = 
D.the top surface of the liquid retards with retardation = 
Solution
The velocity of fluid at the hole is V2 = 
Using continuity equation at the two cross-sections (1) and (2) :
V1 A = V2 a ⇒ V1 =
V2
⇒ acceleration (of top surface) = −
= −
a1 = −
⇒a1 = 
Using continuity equation at the two cross-sections (1) and (2) :
V1 A = V2 a ⇒ V1 =
V2⇒ acceleration (of top surface) = −
= −
a1 = −
⇒a1 = Create a free account to view solution
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