Fluid MechanicsMedium
Question
There is a small hole in the bottom of a fixed container containing a liquid upto height ′h′. The top of the liquid as well as the hole at the bottom are exposed to atmosphere. As the liquid comes out of the hole. (Area of the hole is ′a′ and that of the top surface is ′A′) :
Options
A.the top surface of the liquid accelerates with acceleration = g
B.the top surface of the liquid accelerates with acceleration = 
C.the top surface of the liquid retards with retardation = 
D.the top surface of the liquid retards with retardation = 
Solution
The velocity of fluid at the hole is V2 = 
Using continuity equation at the two cross-sections (1) and (2) :
V1 A = V2 a ⇒ V1 =
V2
⇒ acceleration (of top surface) = −
= −
a1 = −
⇒a1 = 
Using continuity equation at the two cross-sections (1) and (2) :
V1 A = V2 a ⇒ V1 =
V2⇒ acceleration (of top surface) = −
= −
a1 = −
⇒a1 = Create a free account to view solution
View Solution FreeMore Fluid Mechanics Questions
The density of ice is x gm/cc and that of water is y gm/cc. What is the change in volume in cc, when m gm of ice melts?...A block of ice floats on a liquid of density 1.2 in a beaker then level of liquid when ice completely melt : -...A beaker filled with water is accelerated at a m/s² in the +x direction. The surface of the water shall make an angle...An engine pump is used to pump a liquid of density ρ continuously through a pipe of cross-sectional area A. If the ...A beaker with a liquid of density 1.4 g cm-3 is in balance over one pan of a weighing machine as shown in the figure. If...