Properties of matterMedium
Question
When a part of a straight capillary tube is placed vertically in a liquid, the liquid raises upto certain height h . If the inner radius of the capillary tube, density of the liquid and surface tension of the liquid decrease by $1\%$ each, then the height of the liquid in the tube will change by $\_\_\_\_$ $\%$.
Options
A.-1
B.+3
C.-3
D.+1
Solution
$h = \frac{2Tcos\theta}{\rho gr}$
$$\begin{matrix} & \frac{\Delta h}{h}\% = \frac{\Delta T}{T}\% - \frac{\Delta\rho}{\rho}\% - \frac{\Delta r}{r}\% \\ & \frac{\Delta h}{h}\% = 1 + 1 + 1 \\ & \frac{\Delta h}{h} = + 1\% \end{matrix}$$
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