Permutation and CombinationHard
Question
Out of 16 players of a cricket team, 4 are bowlers and 2 are wicket keepers. A team of 11 players is to be chosen so as to contain at least 3 bowlers and at least 1 wicketkeeper. The number of ways in which the team be selected, is
Options
A.2400
B.2472
C.2500
D.960
Solution
Number of bowlers = 4
Number of wicketkeeper = 2
Let total number required selection
4C3 . 2C1 .10C7 + 4C4 .2C1 .10C6 + 4C3 . 2C2 .10C6 + 4C4 . 2C2 .10C5
960 + 420 + 840 + 252
= 2472
Number of wicketkeeper = 2
Let total number required selection
4C3 . 2C1 .10C7 + 4C4 .2C1 .10C6 + 4C3 . 2C2 .10C6 + 4C4 . 2C2 .10C5
960 + 420 + 840 + 252
= 2472
Create a free account to view solution
View Solution FreeMore Permutation and Combination Questions
The number of ways to put five letters in five envelopes when any one letter is kept in right envelope and four letters ...The number of ways in which a mixed double tennis game can be arranged from amongst 9 married couple if no husband & wif...A box contains 6 balls which may be all of different colours or three each of two colours or two each of three different...How many nine digit numbers can be formed using the digits 2, 2, 3, 3, 5, 5, 8, 8, 8 so that the odd digits occupy even ...If function f(x) = , (fof) (√4)...