Permutation and CombinationHard
Question
The number of ways in which a mixed double tennis game can be arranged from amongst 9 married couple if no husband & wife plays in the same game is:
Options
A.756
B.3024
C.1512
D.6048
Solution
There are 9 married couple so first we select 2
man out of 9 and then we select 2 women out of
rest 7 then, we arranged them, so required no. is 9C2 × 7C2 × 2! = 3 6× 21 × 2 = 1512
man out of 9 and then we select 2 women out of
rest 7 then, we arranged them, so required no. is 9C2 × 7C2 × 2! = 3 6× 21 × 2 = 1512
Create a free account to view solution
View Solution FreeMore Permutation and Combination Questions
Let Tn be the number of all possible triangles formed by joining vertices of an n-sided regular polygon. If Tn+1 - Tn = ...The number of proper divisors of apbqcrds where a, b, c, d are primes & p, q, r, s ∈ N is -...Number of ways of placing 5 identical balls in 3 identical boxes (no box remains empty), is -...If 15Pr = 2730, then the value of r is-...The straight lines I1, I2, I3 are parallel and lie in the same plane. A total number of m points are taken on I1; n poin...