Permutation and CombinationHard
Question
How many nine digit numbers can be formed using the digits 2, 2, 3, 3, 5, 5, 8, 8, 8 so that the odd digits occupy even positions?
Options
A.7560
B.180
C.16
D.60
Solution
Even place
There are four even places and four odd digit number so total number of filling is
rest are also occupy is 
ways
Hence total number of ways =
= 60
There are four even places and four odd digit number so total number of filling is
rest are also occupy is waysHence total number of ways =
= 60Create a free account to view solution
View Solution FreeMore Permutation and Combination Questions
The number of words formed from letters of the word ′EAMCET′ so that no two vowels come together, is-...Eleven animals of a circus have to be placed in eleven cages, one in each cage. If four of the cages are too small for s...There are 2 identical white balls, 3 identical red balls and 4 green balls of different shades. The number of ways in wh...The number of ways selecting 8 books from a library which has 10 books each of Mathematics, Physics, Chemistry and Engli...A five digits number divisible by 3 is to be formed using the numbers 0, 1, 2, 3, 4 and 5, without repetition. The total...