Permutation and CombinationHard
Question
How many nine digit numbers can be formed using the digits 2, 2, 3, 3, 5, 5, 8, 8, 8 so that the odd digits occupy even positions?
Options
A.7560
B.180
C.16
D.60
Solution
Even place
There are four even places and four odd digit number so total number of filling is
rest are also occupy is 
ways
Hence total number of ways =
= 60
There are four even places and four odd digit number so total number of filling is
rest are also occupy is waysHence total number of ways =
= 60Create a free account to view solution
View Solution FreeMore Permutation and Combination Questions
The number of ways in which at least one fruit can be selected from 5 oranges, 4 apples and 3 bananas is-...N = 22 . 33 . 54 . 7, then -...Assuming the balls to be identical except for difference in colours, the number of ways in which one or more balls can b...There are 12 points in a plane. The number of the straight lines joining any two of them when 3 of them are collinear is...The value of the expression $^{47}C_4 + \displaystyle\sum_{j=1}^{5} {}^{(52-j)}C_3$ is equal to...