DeterminantHard
Question
Let f(x) = 
, then
, thenOptions
A.fn (1) is indepedent of a
B.fn (1) is indepedent of n
C.fn(1) depends on a and n
D.y = a(x - fn (1)) represents a straight line through the origin
Solution
f(x) = 
f′(x) =
f′(x) =
fn(x) =
fn(1) =
= (-1)n n!
= 0
and y = a (x - fn(1))
y = ax
f′(x) =
f′(x) =
fn(x) =
fn(1) =
= (-1)n n!
= 0and y = a (x - fn(1))
y = ax
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