DeterminantMedium
Question
If ᐃ1 = 
and ᐃ2 = 
are given, then-
and ᐃ2 = are given, then- Options
A.ᐃ1 = 3(ᐃ2)2
B.
ᐃ1 = 3ᐃ2
ᐃ1 = 3ᐃ2C.ᐃ1 = 3(ᐃ2)2
ᐃ1 = 3(ᐃ2)2D.ᐃ1 = 3(ᐃ2)3/2
Solution
ᐃ1 = 
ᐃ2 = 
[1(x2 - ab) ] + [x(x - 0) - b(0 - 0) + b(0 - a)] + [(x(x - 0) - b(a - 0) + b(0)]
x2 - ab + x2 - ab + x2 - ab
3x2 - 3ab = 3(x2 - ab) = 3 ᐃ2
but ᐃ2 =
= x(x) - ab
ᐃ2 = (x2 - ab)
ᐃ2 = [1(x2 - ab) ] + [x(x - 0) - b(0 - 0) + b(0 - a)] + [(x(x - 0) - b(a - 0) + b(0)]
x2 - ab + x2 - ab + x2 - ab
3x2 - 3ab = 3(x2 - ab) = 3 ᐃ2
but ᐃ2 =
= x(x) - abᐃ2 = (x2 - ab)
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