DeterminantHard

Question

If ᐃ1 = and ᐃ2 = are given, then-

Options

A.1 = 3(ᐃ2)2
B.1 = 3ᐃ2
C.1 = 3(ᐃ2)2
D.1 = 3(ᐃ2)3/2

Solution

ᐃ1 =           ᐃ2 =

[1(x2 - ab) ] + [x(x - 0) - b(0 - 0) + b(0 - a)] + [(x(x - 0) - b(a - 0) + b(0)]
x2 - ab + x2 - ab + x2 - ab
3x2 - 3ab = 3(x2 - ab) = 3 ᐃ2
but ᐃ2 = = x(x) - ab
2 = (x2 - ab)

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