DeterminantHard

Question

Value of the ᐃ = is

Options

A.0
B.(a3 - 1) (a6 - 1) (a9 - 1)
C.(a3 + 1) (a6 + 1) (a9 + 1)
D.a15 - 1

Solution


Applying R3 → R3 - R2, R2 → R2 - R1
= = a3a5 = 0

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