DeterminantHard

Question

Value of the ᐃ = is

Options

A.0

B.(a³ - 1) (a⁶ - 1) (a⁹ - 1)

C.(a³ + 1) (a⁶ + 1) (a⁹ + 1)

D.a¹⁵ - 1

Solution

Applying R₃ → R₃ - R₂, R₂ → R₂ - R₁
= = a³a⁵ = 0

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