Circular MotionHard
Question
A stone of mass 1 kg tied to a light inextensible string of length L = 10/3 m, whirling in a circular path in a vertical plane. The ratio of maximum tension in the string to the minimum tension in the string is 4, If g is taken to be 10 m/s2, the speed of the stone at the highest point of the circle is :
Options
A.10 m/s
B.5√2 m/s
C.10√3 m/s
D.20 m/s
Solution
Maximum tension in string at lowest
Tmax =
− mg .....(1)
maximum tension in string at heighest point.
Tmin =
− mg .....(2)
from energy conservation
mv2LP = 2mgL +
mv2HP .....(3)
from (1) & (3)
Tmax =
+ 5 mg ...(4)
from (2) & (4)
4 =
=
⇒ 3mv3HP 9 mgL
⇒ VHP =
= 10 m/s Ans.
Tmax =
maximum tension in string at heighest point.
Tmin =
from energy conservation
from (1) & (3)
Tmax =
from (2) & (4)
4 =
⇒ VHP =
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