Circular MotionMedium
Question
On horizontal smooth surface a mass of 2 kg is whirled in a horizontal circle by means of a string at an initial angular speed of 5 revolutions per minute. Keeping the radius constant the tension in the string is doubled. The new angular speed is nearly:
Options
A.14 rpm
B.10 rpm
C.2.25 rpm
D.7 rpm
Solution
T = mω2r
⇒ T1 = 2T = mω12 r
ω1 = √2 ω = √2 × 5 = √50 ~ 7 rev/min Ans.
⇒ T1 = 2T = mω12 r
ω1 = √2 ω = √2 × 5 = √50 ~ 7 rev/min Ans.
Create a free account to view solution
View Solution FreeMore Circular Motion Questions
What is the minimum velocity with which a body of mass m must enter a vertical loop of radius R so that itcan complete t...A coin placed on a rotating table just slips if it is placed at a distance 4r from the centre. On doubling the angular v...An insect crawls up a hemishperical surface very slowly (see the figure). The coefficient of friction between the surfac...A stone is projected with speed u and angle of projection is θ. Find radius of curvature at t = 0....A bob is whirled in a horizontal plane by means of a string with an initial speed of $\omega rpm$. The tension in the st...