Circular MotionHard
Question
On horizontal smooth surface a mass of 2 kg is whirled in a horizontal circle by means of a string at an initial angular speed of 5 revolutions per minute. Keeping the radius constant the tension in the string is doubled. The new angular speed is nearly:
Options
A.14 rpm
B.10 rpm
C.2.25 rpm
D.7 rpm
Solution
T = mω2r
⇒ T1 = 2T = mω12 r
ω1 = √2 ω = √2 × 5 = √50 ~ 7 rev/min Ans.
⇒ T1 = 2T = mω12 r
ω1 = √2 ω = √2 × 5 = √50 ~ 7 rev/min Ans.
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