Circular MotionHard
Question
A large mass M hangs stationary at the end of a light string that passes through a smooth fixed tube to a small mass m that moves around in a horizontal circular path. If l is the length of the string from m to the top end of the tube and θ is angle between this part and vertical part of the string as shown in the figure, then time taken by m to complete one circle is equal to
Options
A.
B.
C.
D.
Solution
For M to be stationary
T = Mg .... (1)
Also for mass m,
T cos θ = mg .... (2)
T sin θ =
.... (3) dividing (3) by (2)
tan θ =
⇒ v = 
Time period =
= 
From (1) and (2) cos θ =
then time period = 2π
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