Circular MotionHard
Question
A block of mass 0.1 kg is held against a wall applying a horizontal force of 5 N on the block. If the coefficient of friction between the block and the wall is 0.5, the magnitude of the frctional force acting on the block is
Options
A.2.5 N
B.0.98 N
C.4.9 N
D.0.49 N
Solution
N = 5 N
(f)max = μ N = (0.5)(5) = 2.5N
For vertical equilibrium of the block
f = mg = 0.98N < (f)max
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