Circular MotionMedium
Question
Three identical particles are joined together by a thread as shown in figure. All the three particles are moving on a smooth horizontal plane about point O. If the speed of the outermost particle is v0, then the ratio of tensions in the three sections of the string is :
(Assume that the string remains straight)
(Assume that the string remains straight)
Options
A.3 : 5 : 7
B.3 : 4 : 5
C.7 : 11 : 6
D.3 : 5 : 6
Solution
ω = const., for all three particles
ω =
TC = mω2 3l
TB – TC = mω2 2l
TB = 5 mω2l
TA – TB = mω2l
TA = 6 mω2l
TC : TB : TA : : 3 : 5 : 6 Ans.
ω =
TC = mω2 3l
TB – TC = mω2 2l
TB = 5 mω2l
TA – TB = mω2l
TA = 6 mω2l
TC : TB : TA : : 3 : 5 : 6 Ans.
Create a free account to view solution
View Solution FreeMore Circular Motion Questions
A machine, in an amusement park, consists of a cage at the end of one arm, hinged at O. The cage revolves along a vertic...A particle is moving in a circle :...A particle is acted upon by a force of constant magnitude which is always perpendicular to the velocity of the particle,...For a curved track of radius R, banked at angle θ (Take v0 = $\sqrt{Rg\tan\theta}$ )...A car moving on a circular path of length 4π meter experiences a force of 6N towards the center of the path. If the...