Indefinite IntegrationHard
Question
The value of ∫(x - 1)e-x dx is equal to
Options
A.-xex + C
B.xex + C
C.-xe-x + C
D.xe-x + C
Solution
∫(x - 1)e-x dx
= (x - 1) ∫e-x dx -
= - (x - 1) e-x - e-x + C = - xe-x + C
= (x - 1) ∫e-x dx -
= - (x - 1) e-x - e-x + C = - xe-x + C Create a free account to view solution
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