Indefinite IntegrationHard
Question
The value of
dx is equal to
dx is equal to Options
A.
+ C
+ CB.ln (sin x + cos x) + C
C.ln (sin x - cos x) + C
D.ln (sin x + cos x)2 + C
Solution
I = 
Put sin x + cos x = t ⇒ (cos x - sin x) dx = dt
⇒ I =
= ln |t| + C = ln|sin x + cos x| + C
Put sin x + cos x = t ⇒ (cos x - sin x) dx = dt⇒ I =
= ln |t| + C = ln|sin x + cos x| + C Create a free account to view solution
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