FunctionHard
Question
Let 0 < α, β, γ < 
are the solutions of the equations cos x = x, cos(sin x) = x and sin(cos x) = x respectively, then
are the solutions of the equations cos x = x, cos(sin x) = x and sin(cos x) = x respectively, thenOptions
A.α < β < γ
B.γ < α < β
C.β < α < γ
D.γ < β < α
Solution
Equation (1) is cosx = x equation (2) is cos(sinx) = x and equation (3) is cosx = sin-1x is
Since sinx ≤ x ⇒ cos(sinx) ≥ cosx now drawing the graphs of the functions we see that γ < α < β
Since sinx ≤ x ⇒ cos(sinx) ≥ cosx now drawing the graphs of the functions we see that γ < α < β
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