FunctionHard
Question
Let y be an implicit function of x defined by x2x - 2xx cot y - 1 = 0. Then y′(1) equals
Options
A.-1
B.1
C.log 2
D.- log 2
Solution
x2x - 2xx cot y - 1 = 0 .....(1)
Now x = 1,
1 - 2 coty - 1 = 0 ⇒ coty = 0 ⇒ y =
Now differentiating eq. (1) w.r.t. ′x′
2x2x (1 + log x)- 2[xx(-cosec2y)
+ coty xx(1 + log x)] = 0
Now at
2(1 + log 1) - 2
= 0
⇒
Now x = 1,
1 - 2 coty - 1 = 0 ⇒ coty = 0 ⇒ y =
Now differentiating eq. (1) w.r.t. ′x′
2x2x (1 + log x)- 2[xx(-cosec2y)
+ coty xx(1 + log x)] = 0Now at
2(1 + log 1) - 2
= 0⇒
Create a free account to view solution
View Solution FreeMore Function Questions
Let f : R → R be a function such that f(0) = 1 and for any x, y ∈ R, f(xy + 1) = f(x) f(y) - f(y) - x + 2. T...If f : R → R, g : R → R and f(x) = 3x + 4 and (gof) (x) = 2x − 1, then the value of g(x) is -...Suppose, f(x) = (x + 1)2 for x ≥ - 1 If g (x) is the function whose graph is reflection of the graph of f (x) with...Which of the following pair of functions are identical -...In the following, odd function is -...