CalorimetryHard
Question
A steel rod 25 cm long has a cross-sectional area of 0.8 cm2. Force required to stretch this rod by the same amount as the expansion produced by heating it through 10oC is:
(Coefficient of linear expansion of steel is 10-5/oC and Young’s modulus of steel is 2 × 1010 N/m2.)
(Coefficient of linear expansion of steel is 10-5/oC and Young’s modulus of steel is 2 × 1010 N/m2.)
Options
A.160 N
B.360 N
C.106 N
D.260 N
Solution
F = 2 × 1010 × 0.8 × 10-4 × 10-5 × 10
= 160 N.
= 160 N.
Create a free account to view solution
View Solution FreeMore Calorimetry Questions
Two large holes are cut in a metal sheet. If this is heated, distances AB and BC, (as shown)...5 kg of steam at 100oC is mixed with 10 kg of ice at 0oC . Choose correct alternative /s(Given swater = 1 cal/goC, LF = ...An ideal gas with pressure P, volume V and temperature T is expanded isothermally to a volume 2V and a final pressure PI...A liquid with coefficient of volume expansion γ is filled in a container of a material having the coefficient of li...Steam at 100o C is passed into 1.1 kg of water contained in a calorimeter of water equivalent 0.02 kg at 15o C till the ...