CalorimetryHard
Question
A steel rod 25 cm long has a cross-sectional area of 0.8 cm2. Force required to stretch this rod by the same amount as the expansion produced by heating it through 10oC is:
(Coefficient of linear expansion of steel is 10-5/oC and Young’s modulus of steel is 2 × 1010 N/m2.)
(Coefficient of linear expansion of steel is 10-5/oC and Young’s modulus of steel is 2 × 1010 N/m2.)
Options
A.160 N
B.360 N
C.106 N
D.260 N
Solution
F = 2 × 1010 × 0.8 × 10-4 × 10-5 × 10
= 160 N.
= 160 N.
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