Application of DerivativeHard
Question
Using differentials, find the approximate value of 
Options
A.5.02
B.5.01
C.5.03
D.5.04
Solution
= 
Let x = 25 and ᐃx = 0.2 such that f(x) = √x
∴ f′ (x) =
∴ f(x +ᐃx) = f(x) + f′(x). ᐃx
= √x + 
. ᐃx
× 0.2
= 5 + 
= 5 + 0.02 = 5.02Create a free account to view solution
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