Trigonometric EquationHard
Question
If 
(g(t))2 + C, where C is a constant, then g(2) is equal to :
(g(t))2 + C, where C is a constant, then g(2) is equal to :Options
A.1/√5 log (2+√5)
B.1/2 log (2+√5)
C.2 log (2+√5)
D.log (2+√5)
Solution
I = 
put u = log(t +
)
du =
dt
I = ∫u du =
+ c
g(t) = log(t +
)
g(2) = log(2 + √5)
put u = log(t +
)du =
dtI = ∫u du =
+ cg(t) = log(t +
)g(2) = log(2 + √5)
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