Trigonometric EquationHard
Question
Number of ordered pairs (a, x) satisfying the equation sec2( a + 2) x + a2 - 1 = 0; - π < x < π is -
Options
A.2
B.1
C.3
D.Infinite
Solution
tan2 (a + 2)x + a2 = 0
⇒ tan2 (a + 2)x = 0 and a2 = 0
tan2 2x = 0 ⇒ a = 0 ordered pair (a, x)
x = 0,
, -
⇒ a = 0 (0, 0) (0, π/2) (0, -π/2)
⇒ tan2 (a + 2)x = 0 and a2 = 0
tan2 2x = 0 ⇒ a = 0 ordered pair (a, x)
x = 0,
Create a free account to view solution
View Solution FreeMore Trigonometric Equation Questions
The general solution ofsin x -3 sin 2x + sin 3x = cos x - 3 cos 2x + cos 3x is -...The general value of θ satisfying the equation sin2θ - 2cosθ + 1/4 = 0...The locus of the orthocentre of the triangle formed by the lines (1 + p)x - py + p(1 + p) = 0, (1 + q)x - qy + q(1 + q) ...The general solutions of the equation sec2 x = √2(1 − tan2x) are given by-...A line with direction cosines proportional to 2, 1, 2 meets each of the lines x = y + a = z and x + a = 2y = 2z. The co-...