Atomic StructureHard

Question

At temperatuere T, the average kinetic energy of any particle is KT. The de Broglie wavelength follows the order :

Options

A.Visible photon > Thermal neutron > Thermal electron
B.Thermal proton > Thermal electon > Visible photon
C.Thermal proton > Visible photon > Thermal electron
D.Visible photon > Thermal electron > Thermal neutron

Solution

De-broglie wavelength (for particles) =
As temperature is same, KE is same. So, λ ∝
Hence λdb (electron) > λdb (neutron)

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