Atomic StructureHard
Question
At temperatuere T, the average kinetic energy of any particle is
KT. The de Broglie wavelength follows the order :
Options
A.Visible photon > Thermal neutron > Thermal electron
B.Thermal proton > Thermal electon > Visible photon
C.Thermal proton > Visible photon > Thermal electron
D.Visible photon > Thermal electron > Thermal neutron
Solution
De-broglie wavelength (for particles) = 
As temperature is same, KE is same. So, λ ∝
Hence λdb (electron) > λdb (neutron)
As temperature is same, KE is same. So, λ ∝
Hence λdb (electron) > λdb (neutron)
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