Atomic StructureHard
Question
At temperatuere T, the average kinetic energy of any particle is
KT. The de Broglie wavelength follows the order :
Options
A.Visible photon > Thermal neutron > Thermal electron
B.Thermal proton > Thermal electon > Visible photon
C.Thermal proton > Visible photon > Thermal electron
D.Visible photon > Thermal electron > Thermal neutron
Solution
De-broglie wavelength (for particles) = 
As temperature is same, KE is same. So, λ ∝
Hence λdb (electron) > λdb (neutron)
As temperature is same, KE is same. So, λ ∝
Hence λdb (electron) > λdb (neutron)
Create a free account to view solution
View Solution FreeMore Atomic Structure Questions
X X1 + H2O → HX1 + HOXSelect the correct statement for above reaction :...How many of the following compounds have used their d-orbital in hybridisationCF4, SF4, I3-, SOF4, PF3Cl2, SnCl2, SO42-...Photon of which light has maximum energy :...The probability of finding Py electron is zero in...In the Rutherford scattering experiment, the number of alpha particles scattered at an angle θ = 60o is 36 per minute. T...