Atomic StructureHard
Question
In H-atom, if ′x′ is the radius of the first Bohr orbit, de Broglie wavelength of an electron in 3rd orbit is :
Options
A.3 π x
B.6 π x
C.9x/2
D.x/2
Solution
r1 = 0.529 (Ao)
r3 = 0.529 × (3)2 (Ao) = 9x
so, λ =
= 6 πx.
r3 = 0.529 × (3)2 (Ao) = 9x
so, λ =
= 6 πx.Create a free account to view solution
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