Magnetic field due to currentHard

Question

A proton (mass m) accelerated by a potential difference V files through a uniform transverses magnetic field B. The field occupies a region of space by width ′d′. If ′α′be the angle of deviation of proton from initial direction of motion (see figure,) the value of sin α will be
                                     

Options

A.
B.
C.
D.

Solution

    
sin α = d/R
sin α =
sin α = Bd
∴ 

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