Magnetic field due to currentHard
Question
There are constant electron field E0ĵ & magnetic field B
present between plates P and P′. A particle of mass m is projected from plate p′ along y axis with velocity v1. After moving on the curved path, it passes through point A just grazing the plate P with velocity v2. The magnitude of impulse (i.e.
) provided by magnetic force during the motion of particle from origin to point A is : -


Options
A.m|v2 - v1|
B.
C.mv1
D.mv2
Solution
Electric force is only responsible for the change in momentum along y - axis. Therefore impulse provide by magnetic force is JB = mv2.
Create a free account to view solution
View Solution FreeMore Magnetic field due to current Questions
Two cylindrical straight and very long non magnetic conductors A and B , insulated from each other, carry a current I in...A wire is parallel to one arm of a square current carrying loop, which also carries current. Now at any point A within t...Magnetic field of earth is 0.3 gauss. A magnet oscillating with rate of 5 oscillation/min. How much the magnetic field o...The force acts for a conducting loop when magnetic fields is :-...An electron (e/m) = 1.76 × 1011 coulomb/kg] enters a region where there is a uniform magnetic field of induction 1....