Magnetic field due to currentHard
Question
From a cylinder of radius R, a cylinder of radius R/2 is removed, as shown. Current flowing in the remaining cylinder is I. Magnetic field strength is -
Options
A.zero at point A
B.zero at point B
C.
at point A
at point AD.at point B
at point BSolution
I1 =
Field at A = BI1 + BI2 = 0 +
Field at B = BI1 + BI2 =
+ 0Create a free account to view solution
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